(3x-5)/x^2-2

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Solution for (3x-5)/x^2-2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x-5)/(x^2)-2 = 0

(3*x-5)/(x^2)+(-2*x^2)/(x^2) = 0

3*x-2*x^2-5 = 0

3*x-2*x^2-5 = 0

3*x-2*x^2-5 = 0

DELTA = 3^2-(-5*(-2)*4)

DELTA = -31

DELTA < 0

1 = 0

1/(x^2) = 0

1/(x^2) = 0 // * x^2

1 = 0

x belongs to the empty set

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